Originally posted by Smoothaccel:
I find this hard to digest. An example: If I understand what you are saying, Since the torque/acceleration is the same/constant between 3500 and 7500, two identical cars (NSX) would have no advantage/disadvantage if one were to stay in the powerband of 3500 to 5500 and the other 5500 to 7500 ?!?.
I think you're misunderstanding something. What I am saying is that torque/acceleration is relatively constant
within the same gear. So, for example, if you have a stock '91 NSX in first gear, it accelerates at roughly the same rate from 10 to 20 mph as it does from 30 to 40 mph. You may
think it accelerates faster from 30 to 40 mph than from 10 to 20 mph, because it's a lot louder, but the rate of acceleration is close to equal (0.75 second 10-20 vs 0.68 second 30-40).
However, if you have a stock '91 NSX, accelerating from 30 to 40 mph
in first gear, which might be from 5500 to 7500 RPM, it will accelerate a lot faster (0.68 second) than a stock '91 NSX accelerating from 30 to 40 mph
in second gear, which takes around 1.2 seconds and might be from 3500 to 5500 RPM.
The reason why you want the revs to be higher is
not because the engine provides all that much more force (torque) at the higher revs. (People think it provides more force because it sounds louder in the VTEC range - but it really doesn't.) The reason you want the revs to be higher is because the lower gear allows more of that force to be applied to the wheels.
Any NSX will achieve maximum acceleration by shifting at or around redline, and that's the assumption built into the acceleration numbers that Bob has calculated. I was not suggesting that an NSX upshift at 5500 RPM in any of the examples used above.
If this doesn't help clear up your confusion, please ask again and I'll try to explain.
[This message has been edited by nsxtasy (edited 24 September 2002).]