Per you question: Ideally, the availabilty of oxygen and the density of air will increase slightly as the temperature goes down. The ideal gas formula describes the relationship: PV =nRT
Where;
P - pressure
V- volume
n - number of gas molecules (O2 = 0.20 x n)
R - universal gas constant
T - absolute temperature (degrees Rankine, not Farenheit)
80 deg. F = 540 deg. R
25 deg. F = 485 deg. R
So, as the temp declines and the volume is held fixed (displacement = 3.0 or 3.2 liters), the number of molecules in that volume increases and hence the greater number of oxygen molecules that are available for combustion). The power (HP) is proportional to the amount of chemical energy ((V)gasoline + (V)O2 + spark) that is converted to kinetic energy (
force x moment arm x
rotational velocity). This being said, the increase in HP is really an increase in torque as the RPM's are not increasing. I also think that the temp sensor allows for an increase in the volume of fuel delivered per stroke so that you have a more complete cumbustion of the air/fuel mixture as well as a slight increase in the volume of fuel combusted per power stroke. How much more? The math works out to about an 11% increase, not considering the increase in fuel which is handled by EMM, waste heat loss and frictional loss. So, at 8,000 rpm and at about 245 HP (NA1) at the wheels, you could expect about 25 hp increase minus the losses due to waste heat transfer (40%). In other words, you may notice an increase of about 15 HP (about what you thought!).