to continue this analyis... when accelerating out of a turn, the outside driven wheel is more loaded, and is also moving the car a slightly longer distance (compared to the inside wheel). The outside driven wheel must spin faster; viewed another way, the inside driven wheel wants to slip relative to the outside wheel.
a) what does the LSD do ? the clutch holds the inside driven wheel from slipping until the torque exceeds the default settings. In meantime, more power can be applied to the outside driven wheel.
b) what does the higher-torque LSD (ala NSX-R) do ?? Further prevents slip, more so than the regular LSD.
If I understand this correctly, this allows MORE power to be transmitted to the driven wheels BEFORE one of them (the inside) starts to slip.
Is this correct ?
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IIRC, the OE LSD is set at about 40-60 ft-lb; NSX-R is set at about 110 ft-lb; Cunningham's LSD is set to about 150 ft-lb.